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-6x^2-30x^2+42x=0
We add all the numbers together, and all the variables
-36x^2+42x=0
a = -36; b = 42; c = 0;
Δ = b2-4ac
Δ = 422-4·(-36)·0
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1764}=42$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-42}{2*-36}=\frac{-84}{-72} =1+1/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+42}{2*-36}=\frac{0}{-72} =0 $
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